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'''b=80mm''' | '''b=80mm''' | ||
+ | |||
+ | d<sub>m</sub>=1,25*l*z/Φ | ||
l=d<sub>m</sub>*Φ/1,25*z | l=d<sub>m</sub>*Φ/1,25*z | ||
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h<sub>seg</sub>=0,25√b<sup>2</sup>+l<sup>2</sup> | h<sub>seg</sub>=0,25√b<sup>2</sup>+l<sup>2</sup> | ||
+ | |||
+ | h<sub>seg</sub>=0,25√80<sup>2</sup>+63<sup>2</sup> | ||
+ | |||
+ | '''h<sub>seg</sub>=25mm''' | ||
+ | |||
+ | l<sub>t</sub>=1,25*l | ||
+ | |||
+ | l<sub>t</sub>=1,25*63 | ||
+ | |||
+ | '''l<sub>t</sub>=78,75mm''' |
Version vom 19. Mai 2006, 21:28 Uhr
Lösung
b=0,5(da-di
b=0,5(330mm-170mm)
b=80mm
dm=1,25*l*z/Φ
l=dm*Φ/1,25*z
l=250mm*Φ/1,25*10
l=62,83mm≈63mm
hseg=0,25√b2+l2
hseg=0,25√802+632
hseg=25mm
lt=1,25*l
lt=1,25*63
lt=78,75mm